3[x-(2-x)]-5(x+1)=

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Solution for 3[x-(2-x)]-5(x+1)= equation:


Simplifying
3[x + -1(2 + -1x)] + -5(x + 1) = 0
3[x + (2 * -1 + -1x * -1)] + -5(x + 1) = 0
3[x + (-2 + 1x)] + -5(x + 1) = 0

Reorder the terms:
3[-2 + x + 1x] + -5(x + 1) = 0

Combine like terms: x + 1x = 2x
3[-2 + 2x] + -5(x + 1) = 0
[-2 * 3 + 2x * 3] + -5(x + 1) = 0
[-6 + 6x] + -5(x + 1) = 0

Reorder the terms:
-6 + 6x + -5(1 + x) = 0
-6 + 6x + (1 * -5 + x * -5) = 0
-6 + 6x + (-5 + -5x) = 0

Reorder the terms:
-6 + -5 + 6x + -5x = 0

Combine like terms: -6 + -5 = -11
-11 + 6x + -5x = 0

Combine like terms: 6x + -5x = 1x
-11 + 1x = 0

Solving
-11 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1x = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 1x = 0 + 11
1x = 0 + 11

Combine like terms: 0 + 11 = 11
1x = 11

Divide each side by '1'.
x = 11

Simplifying
x = 11

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